Arrange the following carbocations in the decreasing order of stability I. p-Br–C6H4–CH2+ II. C6H5–CH2+ III. p-CH3O–C6H4–CH2+ IV. p-CHO–C6H4–CH2+ V. p-CH3–C6H4–CH2+ Choose the correct answer from the options given below:

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IV > I > II > V > III. The stability of carbocations is influenced by the electron-donating or withdrawing effects of substituents on the aromatic ring. In this case, the p-CHO group is a strong electron-withdrawing group, making the carbocation less stable, while the p-CH3O and p-CH3 groups are electron-donating, enhancing stability. Thus, the order of stability is determined by the strength of these effects, leading to the correct arrangement.

Arrange the following carbocations in the decreasing order of stability I. p-Br–C6H4–CH2+ II. C6H5–CH2+ III. p-CH3O–C6H4–CH2+ IV. p-CHO–C6H4–CH2+ V. p-CH3–C6H4–CH2+ Choose the correct answer from the options given below:

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