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ExamsJEE MainChemistry

Which of the following statements regarding the energy of the stationary state is true in the following one-electron system ? (1) −1.09 × 10^−18 J for second orbit of H atom. (2) +2.18 × 10^−18 J for second orbit of He^+ ion (3) +8.72 × 10^−18 J for first orbit of He^+ ion (4) −2.18 × 10^−18 J for third orbit of Li^2+ ion

  1. −1.09 × 10^−18 J for second orbit of H atom.
  2. +2.18 × 10^−18 J for second orbit of He^+ ion
  3. +8.72 × 10^−18 J for first orbit of He^+ ion
  4. −2.18 × 10^−18 J for third orbit of Li^2+ ion

Correct answer: −2.18 × 10^−18 J for third orbit of Li^2+ ion

Solution

The energy of an electron in a hydrogen-like atom is given by the formula E = -Z² * 13.6 eV / n², where Z is the atomic number and n is the principal quantum number. For Li²⁺, which has Z = 3, the energy for the third orbit (n=3) is calculated to be negative, indicating a bound state, and results in -2.18 × 10^−18 J, making this statement correct.

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