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Consider the following reactions. PbCl2 + K2CrO4 → A + 2KCl (Hot solution) A + NaOH ⇌ B + Na2CrO4 PbSO4 + 4CH3COONH4 → (NH4)2SO4 + X In the above reactions, A, B and X are respectively.

1. Na2[Pb(OH)2], PbCrO4 and (NH4)2[Pb(CH3COO)4]
2. PbCrO4, Na2[Pb(OH)4] and [Pb(NH3)4]SO4
3. Na2[Pb(OH)2], PbCrO4 and [Pb(NH3)4]SO4
4. PbCrO4, Na2[Pb(OH)4] and (NH4)2[Pb(CH3COO)4]

Correct answer: PbCrO4, Na2[Pb(OH)4] and (NH4)2[Pb(CH3COO)4]

Solution

The correct option identifies A as PbCrO4, which forms from the reaction of PbCl2 with K2CrO4, and B as Na2[Pb(OH)4], produced when A reacts with NaOH. X is correctly identified as (NH4)2[Pb(CH3COO)4], resulting from the reaction of PbSO4 with ammonium acetate.

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