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A xenon fluoride compound contains 53.5% xenon by mass. What oxidation state does xenon have in this compound?

1. −4
2. 0
3. +4
4. +6

Correct answer: +6

Solution

131/(131+19n) = 0.535 gives n = 6, so the compound is XeF6 and xenon is +6, not 0.

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