Exams › JEE Main › Chemistry

Match the List-I with List-II List-I A. Carbocation B. C-Free radical C. Nucleophile D. Electrophile List-II I. Species that can supply a pair of electrons II. Species that can receive a pair of electrons III. sp² hybridized carbon with empty p-orbital IV. sp²/sp³ hybridized carbon with one unpaired electron Choose the correct answer from the options given below :

1. A(III), B(IV), C(II), D(I)
2. A(II), B(III), C(I), D(IV)
3. A(IV), B(II), C(III), D(I)
4. A(III), B(IV), C(I), D(II)

Correct answer: A(III), B(IV), C(I), D(II)

Solution

The correct option accurately matches each species with its defining characteristic: a carbocation (A) is an sp² hybridized carbon with an empty p-orbital (III), a free radical (B) has one unpaired electron (IV), a nucleophile (C) can donate a pair of electrons (I), and an electrophile (D) can accept a pair of electrons (II).

Related JEE Main Chemistry questions

• Which statement is correct about hyperconjugation, also called no-bond resonance?
• Lactic acid loses its optical activity when the hydroxyl group is replaced by hydrogen because
• Which is the most suitable technique for separating a mixture of sugars?
• Which of the following compounds fails to give a positive Lassaigne’s test for nitrogen?
• Which statement correctly compares the staggered and eclipsed conformations of ethane?
• Arrange the following carbanions in decreasing order of stability: (I) RC\equiv C^- (II) C_6H_5^- (III) R_2C=CH^- (IV) R_3C–CH_2^-

⚔️ Practice JEE Main Chemistry free + battle 1v1 →