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The IUPAC name of the following compound is : HC ≡ C – CH2 – CH(OH) – CH2 – CH = CH2

1. 4-Hydroxyhept-6-en-1-yne
2. Hept-6-en-1-yn-4-ol
3. 4-Hydroxyhept-1-en-6-yne
4. Hept-1-en-6-yn-4-ol

Correct answer: Hept-1-en-6-yn-4-ol

Solution

The correct option accurately reflects the structure of the compound, indicating the presence of a hydroxyl group at the fourth carbon, a double bond starting at the first carbon, and a triple bond starting at the sixth carbon, following IUPAC naming conventions.

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