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Number of stereoisomers possible for the complexes [CrCl3(py)3] and [CrCl2(ox)2]3− are respectively (py = pyridine, ox = oxalate) (1) 2 & 2 (2) 1 & 2 (3) 2 & 3 (4) 3 & 3

1. 2 & 2
2. 1 & 2
3. 2 & 3
4. 3 & 3

Correct answer: 2 & 3

Solution

The complex [CrCl3(py)3] can exhibit two stereoisomers due to its octahedral geometry and the arrangement of three identical pyridine ligands and three chloride ligands. In contrast, [CrCl2(ox)2]3− can have three stereoisomers because the oxalate ligands can coordinate in different orientations, leading to more possible configurations.

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