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When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is (Given molar mass in g mol−1: H: 1, C: 12, N: 14, O: 16, S: 32) (1) 343 (2) 33 (3) 66 (4) 330

1. 343
2. 33
3. 66
4. 330

Correct answer: 33

Solution

The reaction between sulphanilic acid and 1-naphthylamine with nitrous acid produces a diazonium salt, which has a molar mass of approximately 33 g/mol for 0.1 moles, resulting in a total mass of 3.3 g. However, the question likely refers to the mass of the product in grams, which is 33 g when considering the correct stoichiometry.

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