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Electronic configuration of four elements A, B, C and D are given below: (A) 1s2 2s2 2p5 (B) 1s2 2s2 2p4 (C) 1s2 2s2 2p6 (D) 1s2 2s2 2p2 Which of the following is the correct order of increasing electronegativity (Pauling’s scale)?

1. A < C < B < D
2. A < B < C < D
3. D < A < B < C
4. A < D < B < C

Correct answer: D < A < B < C

Solution

Electronegativity generally increases across a period and decreases down a group in the periodic table. In this case, element D has the lowest electronegativity due to having fewer valence electrons, while element C, with a full outer shell, has the highest electronegativity.

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