Exams › JEE Main › Chemistry

Arrange the following species in order of decreasing radius: F$^-$, F, O, and O$^{2-}$.

1. O2− > F− > F > O
2. F− > O2− > F > O
3. O2− > O > F− > F
4. O2− > F− > O > F

Correct answer: O2− > F− > F > O

Solution

O$^{2-}$ and F$^-$ are isoelectronic with 10 electrons, and O$^{2-}$ is larger because it has fewer protons. For neutral atoms in Period 2, atomic radius decreases from O to F, so the decreasing order is O$^{2-}$ > F$^-$ > F > O.

Related JEE Main Chemistry questions

• Which of the following sequences is incorrectly arranged with respect to the property mentioned alongside it?
• For the element having atomic number 120, which symbol and IUPAC systematic name are correctly paired?
• Which sequence correctly represents the ionization energies of carbon, nitrogen, and oxygen atoms?
• Identify the sequence that is not arranged correctly.
• Identify the statement that is not correct:
• As stated by the Periodic Law, the changes in elemental properties depend on their

⚔️ Practice JEE Main Chemistry free + battle 1v1 →