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Match List – I with List – II. List-I (Pair of Compounds) (A) n-propanol and Isopropanol (B) Methoxypropane and ethoxyethane (C) Propanone and propanal (D) Neopentane and Isopentane List-II (Isomerism) (I) Metamerism (II) Chain Isomerism (III) Position Isomerism (IV) Functional Isomerism

1. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
2. (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
3. (A)-(I), (B)-(III), (C)-(IV), (D)-(II)
4. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Correct answer: (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Solution

The correct option matches each pair of compounds with their respective type of isomerism: n-propanol and isopropanol exhibit position isomerism due to the different positions of the hydroxyl group; methoxypropane and ethoxyethane are metameric isomers as they differ in the alkyl groups attached to the ether oxygen; propanone and propanal are functional isomers since they have different functional groups (ketone vs aldehyde); and neopentane and isopentane show chain isomerism due to their distinct carbon chain structures.

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