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CH3–CH2–CH2–Br + NaOH (C2H5OH) → Product 'A' Product A —(H2O / H+)→ Product 'B' Product A —(diborane, H2O2 / OH−)→ Product 'C' Consider the above reactions, identify product B and product C.

1. B = C = 2-Propanol
2. B = 2-Propanol C = 1-Propanol
3. B = 1-Propanol C = 2-Propanol
4. B = C = 1-Propanol

Correct answer: B = 2-Propanol C = 1-Propanol

Solution

In the first reaction, the alkyl bromide undergoes an elimination reaction with NaOH to form 2-Propanol (Product B). In the second reaction, Product A is oxidized using diborane and hydrogen peroxide, resulting in the formation of 1-Propanol (Product C) through a different pathway.

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