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Compound A formed in the following reaction reacts with B gives the product C. Find out A and B. CH3 – C≡CH + Na → A → CH3 – C≡C – CH2 – CH2 – CH3 + NaBr

1. A = CH3 – C≡CNa+, B = CH3 – CH2 – CH2 – Br
2. A = CH3 – C≡CNa, B = CH3 – CH2 – CH3
3. A = CH3 – CH2 – CH3, B = CH3 – C≡CH
4. A = CH3 – CH = CH2, B = CH3 – CH2 – CH2 – Br

Correct answer: A = CH3 – C≡CNa+, B = CH3 – CH2 – CH2 – Br

Solution

Option A is correct because the reaction of CH3 – C≡CH with sodium forms the sodium acetylide (CH3 – C≡CNa), which can then react with the alkyl bromide (CH3 – CH2 – CH2 – Br) to produce the desired product C.

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