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Match List-I with List-II. List-I Species: (A) Cr2+ (B) Mn+ (C) Ni2+ (D) V+ List-II Electronic distribution: (I) 3d8 (II) 3d3 4s1 (III) 3d4 (IV) 3d5 4s1 Choose the correct answer from the options given below

1. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
2. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
3. (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
4. (A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Correct answer: (A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Solution

The correct option matches the oxidation states of the species with their respective electronic configurations: Cr2+ has a configuration of 3d4 4s1, Mn+ has 3d5 4s1, Ni2+ corresponds to 3d8, and V+ has 3d3 4s1, aligning perfectly with the given pairs.

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