The order of relative stability of the contributing structure is : CH2 = CH — C(=O) — H ↔ CH2 — CH = C(—O:) — H ↔ ⁻CH2 — CH = C(=O) — H Choose the correct answer from the options given below:

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(2) I > II > III. The first structure (I) is the most stable due to the presence of a carbonyl group that is well-aligned with the double bond, allowing for effective resonance stabilization. The second structure (II) has a negative charge on the oxygen, which is less stable than structure I but more stable than the third structure (III), where the negative charge is on a carbon atom, making it the least stable.

The order of relative stability of the contributing structure is : CH2 = CH — C(=O) — H ↔ CH2 — CH = C(—O:) — H ↔ ⁻CH2 — CH = C(=O) — H Choose the correct answer from the options given below:

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