Exams › JEE Main › Chemistry
The number of paramagnetic species from the following is ______. [Ni(CN)4]2−, [Ni(CO)4], [NiCl4]2−, [Fe(CN)6]4−, [Cu(NH3)4]2+, [Fe(H2O)6]2+ and [Fe(H2O)6]3+
- 1
- 2
- 3
- 4
Correct answer: 3
Solution
The correct option is 3 because among the given complexes, [Fe(H2O)6]2+, [Fe(H2O)6]3+, and [Cu(NH3)4]2+ contain unpaired electrons, making them paramagnetic, while the others are either diamagnetic or have all paired electrons.
Related JEE Main Chemistry questions
⚔️ Practice JEE Main Chemistry free + battle 1v1 →