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The formulas of A and B for the following reaction sequence Fructose ── HCN / H3O+ ──> A Fructose ── (i) NaBH4 (ii) HI / P ──> B are -

1. A = C7H14O8, B = C6H14
2. A = C7H13O7, B = C7H14O
3. A = C7H12O8, B = C6H14
4. A = C7H14O8, B = C6H14O6

Correct answer: A = C7H14O8, B = C6H14

Solution

The correct option indicates that compound A, formed from fructose with HCN and H3O+, has a higher degree of saturation and additional functional groups, resulting in C7H14O8. Compound B, produced through reduction and subsequent hydrolysis, simplifies to C6H14, reflecting the loss of oxygen and the formation of a more saturated hydrocarbon.

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