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(C7H5O2)2 → [X] → 2C6H5 + 2CO2 Consider the above reaction and identify the intermediate ‘X’

1. C6H5 – C(=O)⊕
2. C6H5 – C(=O) – O⊖
3. C6H5 – C(=O) – O:
4. C6H5 – C(=O) – O: (with lone pairs as shown)

Correct answer: C6H5 – C(=O) – O: (with lone pairs as shown)

Solution

The correct option represents a resonance-stabilized intermediate where the negative charge on the oxygen can delocalize, facilitating the breakdown into phenyl groups and carbon dioxide. This stability is crucial for the reaction to proceed efficiently.

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