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SO2Cl2 on reaction with excess of water results into acidic mixture SO2Cl2 + 2H2O → H2SO4 + 2HCl 16 moles of NaOH is required for the complete neutralisation of the resultant acidic mixture. The number of moles of SO2Cl2 used is
- 16
- 8
- 4
- 2
Correct answer: 8
Solution
The reaction of SO2Cl2 with water produces one mole of H2SO4 and two moles of HCl, resulting in a total of three moles of acid for each mole of SO2Cl2. To neutralize the acidic mixture, 16 moles of NaOH are needed, indicating that 8 moles of SO2Cl2 were used, as 16 moles of NaOH can neutralize 8 moles of acid.
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