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[Pd(F)(Cl)(Br)(I)]2− has n number of geometrical isomers. Then, the spin-only magnetic moment and crystal field stabilisation energy [CFSE] of [Fe(CN)6]6−, respectively, are: [Note: Ignore the pairing energy]

1. 2.84 BM and −1.6 Δo
2. 1.73 BM and −2.0 Δo
3. 5.92 BM and 0
4. 0 BM and −2.4 Δo

Correct answer: 1.73 BM and −2.0 Δo

Solution

The correct option indicates that [Fe(CN)6]6− is a low-spin complex due to the strong field ligand CN−, resulting in no unpaired electrons, which gives a spin-only magnetic moment of 1.73 BM. The CFSE is calculated based on the splitting of d-orbitals in an octahedral field, leading to a value of −2.0 Δo.

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