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The number of geometrical isomers that can exist for square planar [Pt(Cl)(py)(NH3)(NH2OH)]^+ is - (py = pyridine): (1) 2 (2) 3 (3) 4 (4) 6

1. 2
2. 3
3. 4
4. 6

Correct answer: 3

Solution

The square planar complex [Pt(Cl)(py)(NH3)(NH2OH)]^+ can have different arrangements of its ligands around the platinum center. Given that there are two identical ligands (NH3 and NH2OH) and two different ligands (Cl and py), the possible configurations lead to three distinct geometrical isomers.

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