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Arrange the following carbocations in decreasing order of stability: I. CH2=CH–CH2+ II. CH3–CH2–CH2+ III. C6H5–CH2+

1. I > II > III
2. II > III > I
3. III > II > I
4. III > I > II

Correct answer: I > II > III

Solution

The stability of carbocations is influenced by the ability of surrounding groups to donate electron density. The allylic carbocation (I) is stabilized by resonance, while the primary carbocation (II) is less stable due to lack of resonance and inductive effects. The benzylic carbocation (III) is stabilized by resonance with the aromatic ring, but not as effectively as the allylic structure, making the order I > II > III correct.

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