Exams › JEE Main › Chemistry
Using the following standard reduction potentials: E°(Sc^3+/Sc) = −0.37, E°(Mn^3+/Mn^2+) = +1.57, E°(Cr^2+/Cr) = −0.90, E°(Cu^2+/Cu) = +0.34, which statement is not correct?
- Sc^3+ is highly stable because it has the [Ar]3d^0 4s^0 arrangement.
- Mn^3+ is more stable than Mn^2+.
- Cr^2+ acts as a reducing agent.
- Copper does not liberate H2 when treated with dilute H2SO4.
Correct answer: Sc^3+ is highly stable because it has the [Ar]3d^0 4s^0 arrangement.
Solution
Sc^3+ is not highly stable; rather, it is a strong oxidizing agent due to its empty d-orbitals, making it less stable than its elemental form. The electron configuration does not confer stability in this case.
Related JEE Main Chemistry questions
⚔️ Practice JEE Main Chemistry free + battle 1v1 →