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ExamsJEE MainChemistry

Arrange the following carbanions in decreasing order of stability: (I) RC≡C⁻ (II) C₆H₅⁻ (III) R₂C=CH⁻ (IV) R₃C–CH₂⁻

  1. (I) > (II) > (III) > (IV)
  2. (II) > (III) > (IV) > (I)
  3. (IV) > (II) > (III) > (I)
  4. (IV) > (III) > (II) > (I)

Correct answer: (IV) > (III) > (II) > (I)

Solution

The stability of carbanions is influenced by factors such as resonance and steric hindrance. In this case, the tertiary carbanion (IV) is stabilized by hyperconjugation and inductive effects, while the allylic carbanion (III) benefits from resonance. The phenyl carbanion (II) has some resonance stabilization, but less than (III), and the alkyne carbanion (I) is the least stable due to its high negative charge density and lack of resonance.

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