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The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is [Given The threshold frequency of platinum is 1.3 × 10¹⁵ s⁻¹ and h = 6.6 × 10⁻³⁴ J s.]
- 3.21 × 10⁻¹⁴ J
- 6.24 × 10⁻¹⁶ J
- 8.58 × 10⁻¹⁹ J
- 9.76 × 10⁻²⁰ J
Correct answer: 8.58 × 10⁻¹⁹ J
Solution
The correct option is derived from the equation E = hν, where E is the energy of the photon, h is Planck's constant, and ν is the threshold frequency. By substituting the given values, the energy calculated aligns with the minimum energy required to initiate the photoelectric effect in platinum.
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