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ExamsJEE MainChemistry

The interaction energy of London forces between two particles is proportional to r−x, where r is the distance between the particles. The value of x is: (1) 3 (2) −3 (3) −6 (4) 6

  1. 3
  2. −3
  3. −6
  4. 6

Correct answer: 6

Solution

The instantaneous-dipole induced-dipole (London) interaction energy is proportional to 1/r^6 = r^-6, so the exponent x in r^-x is 6.

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