Exams › JEE Main › Chemistry
In which of the following pairs, the outer most electronic configuration will be the same?
- Cr+ and Mn2+
- Ni2+ and Cu+
- Fe2+ and Co+
- V2+ and Cr+
Correct answer: Cr+ and Mn2+
Solution
Both Cr+ and Mn2+ have the same outermost electronic configuration of 3d5, as the removal of electrons from Cr and Mn leads to a similar distribution in their d orbitals.
Related JEE Main Chemistry questions
- At what wavenumber does the first line of the hydrogen Balmer series occur in the atomic spectrum?
- In the hydrogen emission spectrum, a spectral series has its limit at 12186.3 cm⁻¹. This series is identified as
- Two rapidly moving particles X and Y have de Broglie wavelengths of 1 nm and 4 nm, respectively. If the mass of X is nine times the mass of Y, what is the ratio of their kinetic energies, X: Y?
- Given that Planck’s constant is 6.63 × 10⁻³⁴ J s and the speed of light is 3.0 × 10⁸ m s⁻¹, which of the following is nearest to the wavelength, in nanometres, of light having frequency 8 × 10¹⁵ s⁻¹?
- A lithium ion and a proton are each accelerated through the same potential difference. If their de Broglie wavelengths are λ₁ and λ₂, respectively, and m_(Li) = 9mₚ, what is the ratio λ₁: λ₂?
- The ionisation energy of He⁺ is 19.6 × 10⁻¹⁸ J atom⁻¹. What is the energy of the first stationary state (n = 1) of Li²⁺?
⚔️ Practice JEE Main Chemistry free + battle 1v1 →