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For the Balmer series in the spectrum of H atom, ν̄ = R_H {(1)/(n₁²)-(1)/(n₂²) }, the correct statements among (I) to (IV) are: (I) As wavelength decreases, the lines in the series converge (II) The integer n1 is equal to 2 (III) The lines of longest wavelength corresponds to n2 = 3 (IV) The ionization energy of hydrogen can be calculated from wave number of these lines (1) (II), (III), (IV) (2) (I), (III), (IV) (3) (I), (II), (III) (4) (I), (II), (IV)

1. (1) (II), (III), (IV)
2. (2) (I), (III), (IV)
3. (3) (I), (II), (III)
4. (4) (I), (II), (IV)

Correct answer: (3) (I), (II), (III)

Solution

As wavelength decreases the Balmer lines converge to the series limit (I true); n1 = 2 for Balmer (II true); the longest-wavelength line is the 3->2 transition, n2=3 (III true). The ionization energy of hydrogen requires n1=1, so it cannot be obtained from Balmer lines (IV false). Correct set: (I), (II), (III).

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