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On heating, lead (II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is

1. +2
2. +3
3. +4
4. +5

Correct answer: +3

Solution

Pb(NO3)2 -> NO2 (brown gas A); NO2 cools to N2O4 (colourless B); N2O4 + NO -> N2O3 (blue solid C). In N2O3 the oxidation number of nitrogen is +3.

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