A solution is prepared by dissolving 0.6 g of urea (molar mass = 60 g mol⁻¹) and 1.8 g of glucose (molar mass = 180 g mol⁻¹) in 100 mL of water at 27°C. The osmotic pressure of the solution is: (R = 0.08206 L atm K⁻¹ mol⁻¹)

Question

Accepted Answer

4.92 atm. n = 0.6/60 + 1.8/180 = 0.01 + 0.01 = 0.02 mol in 0.1 L. pi = (n/V)RT = (0.02/0.1)*0.08206*300 = 4.92 atm.

A solution is prepared by dissolving 0.6 g of urea (molar mass = 60 g mol⁻¹) and 1.8 g of glucose (molar mass = 180 g mol⁻¹) in 100 mL of water at 27°C. The osmotic pressure of the solution is: (R = 0.08206 L atm K⁻¹ mol⁻¹)

Solution

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