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K2HgI4 is 40% ionised in aqueous solution. The value of its van't Hoff factor (i) is:

1. 1.6
2. 2.2
3. 2.0
4. 1.8

Correct answer: 1.8

Solution

K2HgI4 dissociates into 3 ions (2 K+ and [HgI4]2-), so n=3. i = 1 + (n-1)*alpha = 1 + 2(0.40) = 1.8.

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