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Given E°Cr3+/Cr = -0.74 V; E°MnO4-/Mn2+ = 1.51 V; E°Cr2O7²-/Cr3+ = 1.33 V; E°Cl2/Cl- = 1.36 V. Based on the data given above, strongest oxidizing agent will be - (1) Mn2+ (2) MnO4- (3) Cl- (4) Cr3+

1. Mn2+
2. MnO4-
3. Cl-
4. Cr3+

Correct answer: MnO4-

Solution

MnO4- is the strongest oxidizing agent because it has the highest standard reduction potential (1.51 V), indicating a greater tendency to gain electrons compared to the other species listed.

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