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Identify the complex that is formed as an outer-orbital complex.

1. [Co(NH₃)₆]³⁺
2. [Mn(CN)₆]⁴⁻
3. [Fe(CN)₆]⁴⁻
4. [Ni(NH₃)₆]²⁺

Correct answer: [Ni(NH₃)₆]²⁺

Solution

The complex [Ni(NH₃)₆]²⁺ is an outer-orbital complex because nickel in this oxidation state utilizes its 3d and 4s orbitals for bonding, allowing for the formation of a six-coordinate complex with a higher coordination number.

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