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Which among the following factors is the most important in making fluorine, the strongest oxidizing halogen ?

1. Hydration enthalpy
2. Ionization enthalpy
3. Electron affinity
4. Bond dissociation energy

Correct answer: Bond dissociation energy

Solution

Fluorine's strong oxidizing ability is primarily due to its low bond dissociation energy, which allows it to easily break bonds and accept electrons from other substances, facilitating oxidation.

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