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An aqueous solution has a freezing point depression corresponding to a freezing point of −0.186 °C. For this same solution, take Kb = 0.512 °C and Kf = 1.86 °C. What is the rise in its boiling point?

1. 0.186 °C
2. 0.0512 °C
3. 0.092 °C
4. 0.2372 °C

Correct answer: 0.0512 °C

Solution

dTf = 0.186 C. dTb = (Kb/Kf) x dTf = (0.512/1.86) x 0.186 = 0.0512 C (index 1).

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