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In view of the signs of ΔrG° for the following reactions: PbO2 + Pb → 2PbO, ΔrG° < 0 SnO2 + Sn → 2SnO, ΔrG° > 0 which oxidation states are more characteristics for lead and tin ?

1. For lead +2, for tin +2
2. For lead +4, for tin +4
3. For lead +2, for tin +4
4. For lead +4, for tin +2

Correct answer: For lead +2, for tin +4

Solution

The negative ΔrG° for the reaction involving Pb indicates that lead commonly exists in the +2 oxidation state, which is more stable and favorable, while the positive ΔrG° for the Sn reaction suggests that tin is more stable in the +4 oxidation state.

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