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For the balanced redox equation X MnO4− + Y C2O4²− + Z H+ → X Mn²+ + 2Y CO2 + Z/2 H2O, what are the values of X, Y and Z in that order?

1. 2, 5, 16
2. 8, 2, 5
3. 5, 2, 16
4. 5, 8, 4

Correct answer: 2, 5, 16

Solution

The correct values of X, Y, and Z are determined by balancing the number of atoms and charges in the redox reaction. In this case, 2 MnO4− ions reduce to 2 Mn²+, while 5 C2O4²− ions oxidize to produce 10 CO2, and 16 H+ ions balance the reaction, ensuring both mass and charge are conserved.

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