Correct answer: 2HI + H2SO4 → I2 + SO2 + 2H2O
In the reaction 2HI + H2SO4 → I2 + SO2 + 2H2O, sulfuric acid acts as an oxidizing agent because it facilitates the oxidation of iodide ions (I-) to iodine (I2), while itself being reduced to sulfur dioxide (SO2). This demonstrates its ability to accept electrons, characteristic of oxidizing agents.