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0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a container of volume 10 m³ at 1000 K. Given R is the gas constant in JK⁻¹ mol⁻¹, x is:

1. 2R/(4 + R)
2. 2R/(4 - R)
3. (4 + R)/(2R)
4. (4 - R)/(2R)

Correct answer: (4 - R)/(2R)

Solution

PV=nRT gives total moles = (200*10)/(R*1000) = 2/R. With 0.5 + x = 2/R, x = 2/R - 0.5 = (4 - R)/(2R).

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