Exams › JEE Main › Chemistry

The compressibility factor for a real gas at high pressure is:

1. 1 + RT/Pb
2. 1
3. 1 + Pb/RT
4. 1 - Pb/RT

Correct answer: 1 + Pb/RT

Solution

At high pressure the molecular-volume term of the van der Waals equation dominates, giving Z = PV/RT = 1 + Pb/RT, i.e. Z > 1.

Related JEE Main Chemistry questions

• A sample of gas has a volume of 300 cc at 27°C under a pressure of 620 mm. What will its volume be at 47°C and 640 mm pressure?
• When the temperature of neon is increased from 20°C to 40°C, by what factor does the mean kinetic energy of its atoms change?
• Which gas is expected to show the greatest departure from ideal-gas behavior?
• Equal amounts (in moles) of hydrogen gas and oxygen gas are kept in a vessel that has a tiny pinhole, allowing both gases to effuse out. By the time one-half of the hydrogen has escaped, what fraction of the oxygen has escaped?
• Which of the following statements is incorrect regarding how raising the temperature affects the distribution of molecular speeds in a gas?
• As stated by the kinetic theory of gases, how does an ideal gas molecule move during the interval between two consecutive collisions?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →