Exams › JEE Main › Chemistry
For emission line of atomic hydrogen from n_i = 8 to n_f = n, the plot of wave number (ν̄) against (1/n²) will be (The Rydberg constant, R_H is in wave number unit)
- Linear with intercept −R_H
- Non linear
- Linear with slope R_H
- Linear with slope −R_H
Correct answer: Linear with slope R_H
Solution
For n_i = 8 -> n_f = n, nu_bar = R_H(1/n^2 - 1/8^2). Plotting nu_bar against (1/n^2) gives a straight line of slope +R_H and intercept -R_H/64.
Related JEE Main Chemistry questions
- At what wavenumber does the first line of the hydrogen Balmer series occur in the atomic spectrum?
- In the hydrogen emission spectrum, a spectral series has its limit at 12186.3 cm⁻¹. This series is identified as
- Two rapidly moving particles X and Y have de Broglie wavelengths of 1 nm and 4 nm, respectively. If the mass of X is nine times the mass of Y, what is the ratio of their kinetic energies, X: Y?
- Given that Planck’s constant is 6.63 × 10⁻³⁴ J s and the speed of light is 3.0 × 10⁸ m s⁻¹, which of the following is nearest to the wavelength, in nanometres, of light having frequency 8 × 10¹⁵ s⁻¹?
- A lithium ion and a proton are each accelerated through the same potential difference. If their de Broglie wavelengths are λ₁ and λ₂, respectively, and m_(Li) = 9mₚ, what is the ratio λ₁: λ₂?
- The ionisation energy of He⁺ is 19.6 × 10⁻¹⁸ J atom⁻¹. What is the energy of the first stationary state (n = 1) of Li²⁺?
⚔️ Practice JEE Main Chemistry free + battle 1v1 →