Exams › JEE Main › Chemistry

Aqueous acetic acid solution has a molarity of 2.05 M and a density of 1.02 g mL⁻¹. What is its molality?

1. 2.28 mol kg⁻¹
2. 0.44 mol kg⁻¹
3. 1.14 mol kg⁻¹
4. 3.28 mol kg⁻¹

Correct answer: 2.28 mol kg⁻¹

Solution

To find the molality, we first need to calculate the mass of the solvent (water) in kilograms. Using the density and molarity, we can determine the mass of the solution and then subtract the mass of acetic acid to find the mass of water. The resulting calculation gives us a molality of 2.28 mol/kg, which is the correct answer.

Related JEE Main Chemistry questions

• A sulphuric acid solution has a concentration of 3.60 M and contains 29% H2SO4 by mass. If the molar mass of H2SO4 is 98 g mol⁻¹, what is the density of the solution in g mL⁻¹?
• Which one of the following substances is absent in clear hard water?
• Fractional distillation is chosen in a situation where
• Car radiators use an aqueous ethylene glycol solution as antifreeze. How much ethylene glycol should be mixed with 5 kg of water so that the freezing point is lowered to -0.3 °C? (K_f = 1.86 K kg mol⁻¹)
• A solution contains a non-volatile solute of molecular mass M₂. Which expression can be used to determine the molecular mass of the solute using osmotic pressure?
• At 298 K, the Henry’s law constant for oxygen is 1.4 × 10⁻³ mol L⁻¹ atm⁻¹. If oxygen is at a partial pressure of 0.5 atm, what mass of oxygen will dissolve in 100 mL of water at 298 K?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →