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For the complex [M(AB)(CD)ef[n+], how many enantiomeric pairs can be formed? Here, AB and CD are unsymmetrical bidentate ligands, while e and f are monodentate ligands.

1. 20
2. 5
3. 10
4. 8

Correct answer: 10

Solution

The complex can form multiple stereoisomers due to the presence of two unsymmetrical bidentate ligands and two monodentate ligands, leading to a total of 10 distinct arrangements. Each arrangement can exist as a pair of enantiomers, resulting in 10 enantiomeric pairs.

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