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Nickel with atomic number 28 forms a diamagnetic complex [NiL4]2− with a mononegative, single-donor ligand. Which hybridisation is used, and how many unpaired electrons are present in the complex?

1. sp3, two
2. dsp2, zero
3. dsp2, one
4. sp3, zero

Correct answer: dsp2, zero

Solution

The complex [NiL4]2− involves nickel in a +2 oxidation state, leading to a d8 electron configuration. In this case, the dsp2 hybridization occurs due to the square planar geometry, and since all electrons are paired, there are zero unpaired electrons.

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