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Which of the following coordination compounds can exist in the greatest number of isomeric forms?

1. [Ir(PR3)2H(CO)]2+
2. [Co(NH3)5Cl]2+
3. [Ru(NH3)4Cl2]+
4. [Co(en)2Cl2]+

Correct answer: [Co(en)2Cl2]+

Solution

[Co(en)2Cl2]+ shows geometrical isomerism (cis and trans) and the cis form is optically active (d and l), giving three isomeric forms total. The MA4B2-type [Ru(NH3)4Cl2]+ gives only cis/trans (two), and [Co(NH3)5Cl]2+ gives one.

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