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Arrange the following species in the order of increasing bond angle:
ClO2, Cl2O, ClO2−
- Cl2O < ClO2 < ClO2−
- ClO2 < Cl2O < ClO2−
- Cl2O < ClO2− < ClO2
- ClO2− < Cl2O < ClO2
Correct answer: ClO2− < Cl2O < ClO2
Solution
Bond angles: ClO2- ~110.5 deg, Cl2O ~111 deg, ClO2 ~117.4 deg. ClO2 is widest because it is an odd-electron radical (single non-bonding electron exerts less repulsion than a lone pair), giving the order ClO2- < Cl2O < ClO2.
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