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What is the hybridization of iodine in ICl7?
- sp3d3
- d2sp3
- sp3d
- sp3
Correct answer: sp3d3
Solution
Iodine in ICl7 undergoes hybridization to accommodate seven bonding pairs, which requires the use of one s, three p, and three d orbitals, resulting in an sp3d3 hybridization.
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