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An aqueous solution has a freezing point of −0.186 °C. If water has Kb = 0.52 K kg mol−1 and Kf = 1.86 K kg mol−1, what is the rise in the boiling point of this solution, in K?

1. 0.52
2. 1.04
3. 1.34
4. 0.052

Correct answer: 0.052

Solution

From freezing point: i*m = dTf/Kf = 0.186/1.86 = 0.1. Then dTb = Kb*(i*m) = 0.52*0.1 = 0.052 K.

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