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Among the following 0.10 M aqueous solutions, which one will show the greatest depression in freezing point, i.e., the lowest freezing temperature?

1. Al2(SO4)3
2. C6H12O6
3. KCl
4. C12H22O11

Correct answer: Al2(SO4)3

Solution

Delta Tf = i*Kf*m, and at equal molality the largest i gives the greatest depression. Al2(SO4)3 -> 2 Al^3+ + 3 SO4^2- gives i = 5, vs KCl i = 2, glucose and sucrose i = 1. So Al2(SO4)3 shows the lowest freezing point.

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