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For a hydrogen atom, the energy of the electron in the ground state is 13.6 eV. What is its energy in the second excited state?
- 1.51 eV
- 3.4 eV
- 6.04 eV
- 13.6 eV
Correct answer: 1.51 eV
Solution
Ground n=1, first excited n=2, second excited n=3. E3 = 13.6/9 = 1.51 eV. The stored 3.4 eV is the n=2 (first excited) value.
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